How to find $z$-intercept of vector equation

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How do I find the $z$-intercept of the vector equation $\left<x,y,z\right> = (6, -2, -3) + t \left<3,-1,-2\right>$

I am so lost, do I set $x$ and $y$ equal to zero, and solve for $z$?

I have no idea how to do this.

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1 Answer

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find the value of t such that x(t)=y(t)=0. then evaluate for z.

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