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Finding the roots of complex numbers

By Emma Valentine
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$(2i)^{1/2}$

$(1-\sqrt{3}i)^{1/2}$

$(-1)^{1/3}$

$(-16)^{1/4}$

How can I find the roots of the complex numbers above?

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2 Answers

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Use de Moivre's theorem: $$z^{1/n} = r^{1/n} \exp \left( i\frac{\theta + 2\pi k}{n} \right)$$ for $k = 0, 1, 2, \ldots, n - 1$. The formula is not difficult to derive as we only need to write $z$ in the polar form and take the $n$th root of both sides.

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Use DeMoivre's formula.

Don't forget that cos and sin functions are $2\pi$ periodic

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