Determine midline equation of the function
By Andrew Adams •
$$ f(x) = -6\sin(3\pi + 4) - 2 $$
Why is $-2$ the midline of the graph of the function? How to prove that?
$\endgroup$ 33 Answers
$\begingroup$So, I think there is a typo in the function definition. There is usually an $x$ involved somewhere. However, to answer your question about the midline, the midline is usually the constant after the trig function. It is $-2$ in this case.
$\endgroup$ 0 $\begingroup$It will make sense if you think about Slope Intercept Form y=mx+b where b is the mid-line. So to break down your equation f(x)=−6sin(3π+4)−2
f(x) >>> y -6 >>> m x >>> sin(3π+4) -2 >>> bYou have the function $$f(x)=-6\sin(3\pi+4x)-2$$ in which the range goes from $-8$ till $4$ therefore the line $$y=-2$$ is such that cuts the graph of the function in points for which $\dfrac{-8+4}{2}=-2$ so your typo should be putting $4$ instead of $4x$.
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